0=-16t^2+14400

Solution for 0=-16t^2+14400 equation:

0=-16t^2+14400

We move all terms to the left:

0-(-16t^2+14400)=0

We add all the numbers together, and all the variables

-(-16t^2+14400)=0

We get rid of parentheses

16t^2-14400=0

a = 16; b = 0; c = -14400;
Δ = b2-4ac
Δ = 02-4·16·(-14400)
Δ = 921600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{921600}=960$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-960}{2*16}=\frac{-960}{32}
=-30
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+960}{2*16}=\frac{960}{32}
=30
$